Given the following lab results, what is the calculated MCH if RBC is 3.01 x 10^12/L, HGB is 9.4 g/dL?

To calculate the Mean Corpuscular Hemoglobin (MCH), the formula used is:

[ \text{MCH} = \left( \frac{\text{HGB (g/dL)} \times 10}{\text{RBC (x 10}^{12}\text{L)}} \right) ]

Using the values provided in the question:

• HGB = 9.4 g/dL

• RBC = 3.01 x 10^12/L

Now, substituting these values into the formula:

[ \text{MCH} = \left( \frac{9.4 \times 10}{3.01} \right) ]

Calculating this step-by-step:

1. Multiply HGB by 10:

( 9.4 \times 10 = 94 )

2. Divide by the RBC count:

( \frac{94}{3.01} \approx 31.2 )

Therefore, when performing the calculation, the value for MCH comes out to be approximately 31.2 pg. This is why the correct answer is recognized as such. The MCH value helps indicate the average amount of hemoglobin per red blood cell,