If the WBC count is 10.5 and there are 5 nRBCs observed in the differential, what is the corrected WBC count?

Prepare your best for the AAB MT Hematology Exam. Utilize flashcards and multiple choice questions, complete with explanations and hints. Ace the exam!

To calculate the corrected white blood cell (WBC) count when nucleated red blood cells (nRBCs) are present, it is essential to use a formula that adjusts the total WBC count based on the number of nRBCs observed. The corrected WBC count helps provide a more accurate representation of the actual white blood cells, excluding the interference caused by nRBCs.

The formula used for this correction is:

[ \text{Corrected WBC Count} = \text{WBC Count} \times \frac{100}{(100 + \text{nRBC Count})} ]

Using the provided values:

  1. Start with the original WBC count of 10.5.

  2. There are 5 nRBCs observed in the differential.

Plugging these numbers into the formula gives:

[ \text{Corrected WBC Count} = 10.5 \times \frac{100}{(100 + 5)} = 10.5 \times \frac{100}{105} ]

Calculating this provides:

[ \text{Corrected WBC Count} = 10.5 \times 0.9524 \approx 10.0 ]

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